5(3x^2-2y^2)+3x(x+3y^2)=

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Solution for 5(3x^2-2y^2)+3x(x+3y^2)= equation: 


Simplifying
5(3x2 + -2y2) + 3x(x + 3y2) = 0
(3x2 * 5 + -2y2 * 5) + 3x(x + 3y2) = 0
(15x2 + -10y2) + 3x(x + 3y2) = 0
15x2 + -10y2 + (x * 3x + 3y2 * 3x) = 0

Reorder the terms:
15x2 + -10y2 + (9xy2 + 3x2) = 0
15x2 + -10y2 + (9xy2 + 3x2) = 0

Reorder the terms:
9xy2 + 15x2 + 3x2 + -10y2 = 0

Combine like terms: 15x2 + 3x2 = 18x2
9xy2 + 18x2 + -10y2 = 0

Solving
9xy2 + 18x2 + -10y2 = 0

Solving for variable 'x'.

The solution to this equation could not be determined.

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